Maths : Mensuration problem
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08-24-2008, 06:55 AM
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The solid in the figure is made up of a cone, a cylinder and a hemisphere. Given that the radius of the cylinder is 8cm, the height of the cylinder is 12cm and the slant height of the cone is 14cm, using pi = 3.142, find
(a)the height of the cone, giving your answer to 2 decimal places,
(b)the volume of the solid, giving your answer correct to the nearest cm^3
(c)the total surface area of the solid, giving your answer correct to the nearest cm^2
the figure is a cone pointing downwards, the cylinder on top of the cone and the hemisphere is an upside down bowl on the cylinder.
I NEED to get the answer for (a). the other 2 is just optional coz I can do that myself once I know the answer for (a).
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08-24-2008, 06:59 AM
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pathagoras using the height of cone (14) and the radius of cylinder(8) since the cyclinder is standing on top of the cone so their radii should be the same.
14^2=8^2+h^2
h=11.5 somewhere around that =P
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08-24-2008, 10:41 AM
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Hmm it has been a year I don't do any high school maths lol. Not sure if I remember or not but I'll give it a try.
radius of cone = radius of cylinder = 8 cm
slant height of cone = 14 cm
Assume that,
the base of a right-angled triangle = 8 cm
the slant length of a right-angled triangle = 14 cm
the height of a right-angled triangle = X (unknown)
Using the formula (forgot whats the name of the formula):
X = square root of (14 - 8) = 2.45 cm (2 decimal places)
Thats my attempt, don't blame me if I'm wrong lol. Just trying to help. If you included the diagram it would be much better lol. The description of the figure you gave there doesnt help much.
Last edited by xCloudz; 08-24-2008 at 10:45 AM..
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